CPU scaling benchmark
workers
9 +1 main
iters total
500M
50000000/stream
elapsed
1158.18 ms
total CPU used
9711.45 ms
speedup
8.39×
vs serial
efficiency
83.9%
of 10× ideal
| stream | spawn ms | spawned@ | work start@ | work end@ | work ms | reap wait ms |
|---|---|---|---|---|---|---|
| 0 (main) | 0 | 24.53 | 24.6 | 1076.63 | 1052.03 | 0 |
| 1 | 1.977 | 1.99 | 26.01 | 1146.47 | 1120.46 | 72.35 |
| 2 | 1.614 | 3.63 | 18.41 | 1040.39 | 1021.98 | 0.13 |
| 3 | 1.634 | 5.28 | 20.25 | 613.35 | 593.1 | 0.19 |
| 4 | 1.555 | 6.85 | 28.45 | 829.52 | 801.07 | 0.21 |
| 5 | 4.377 | 11.24 | 59.43 | 1085.43 | 1026 | 11.58 |
| 6 | 2.055 | 13.31 | 65.63 | 1143.35 | 1077.72 | 66.88 |
| 7 | 1.548 | 14.87 | 65.66 | 1010.59 | 944.93 | 0.22 |
| 8 | 7.825 | 22.71 | 57.23 | 1155.41 | 1098.18 | 78.9 |
| 9 | 1.801 | 24.52 | 57.26 | 1033.24 | 975.98 | 0.23 |
main
w1
w2
w3
w4
w5
w6
w7
w8
w9
fork+handshake
CPU work
parent reap wait
what this measures
Each stream runs a tight integer LCG loop — working set is one CPU register, no memory access,
no shared data. Speedup = sum(stream CPU time) / wall-clock elapsed. Efficiency = speedup / (workers+1).
100% efficiency means perfect linear scaling; less than 100% is the cost of serial fork setup,
reap tail, SMT/core contention.